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Old 20-04-2019, 06:58 PM
r6r6r r6r6r is offline
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Book1 Mass Time Via Pi Associations

Part One

0.0077 * 66.4 = 0.511 28 and that is close to 0.511 { electron mass }.

66.4 is my Pi-Time and explained further below in part two.

Electron mass is 0.511 and the electron repeats itself as the muon-electron and has a much greater mass of 206.7572826.

I.e., 0.511 plus 206.2462826 = the mass of muon-electron 206.7572826.

Above, I change the value of Pi { 3.14 } to 0.0077 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Part Two…..My original pathway to the above

Take the muon-electron mass 206.7572826 and divide it by 66.4 { PI-Time } = 3.11 38144969879518072289156626506 and then add value 2 = 5.11 and then 5.11 divided by 10 = 0.511 mass of electron

Here is how I arrived at Pi-Time { 66.4 }

24.35 22 7 27 and that is #7 in 7th position as found in Pi^4/4{ re-normalization } aka Pi-Time { 66.4 }
…see part four below……

31.00 62 7 66 and that is #7 in the overall 7th position as found in Pi^3{ XYZ } 31.00

The ratio Pi { 3.14 } is close to three and it takes three line segments to complete revolution around the tube, not the whole torus in reference to 7-color mapping https://en.wikipedia.org/wiki/Torus#/media/File:Projection_color_torus.png" of the surface of a torus.

What to do, to arrive at cosmic baseline reference value that can then be used to find mass values of electron or any particle?

Divide Pi by three? 1.0471975511965977461542144610932
Divide Pi-Time by three 66.4 / 3 = 22.13
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Part Three: Four line/level as numerically spiral helixed torus with two inversion-outversions

....1.....................5P............7P........ ...........11P..........13P....................... 17P.......19P..................23P.......25....... .......outer peak of positive surface
-

-
{0}.................................6............. .......................12......................... ..............18.................................. .24..................inside toroidal tube
................3................................. ..{9}.........................................15.. ...................................21............. .......................inside toroidal tube
-

-
...........2..........4........................8.. .........10...........................{14}......16 .......................20..........22............. .......26........inner peak of negative surface.

1...2-4 is the first set of three surface set of nodal points, plus, the inside-the-tube, nuclear reality nodal point 3.

5-7..8 is the 2nd set of three surface nodal points, plus, the inside-the-tube, nuclear reality nodal point 6.

10...11-13 is the three surface set of nodal points, plus the inside-the-tube, nuclear reality 12, and this is third set of nodal points that, total to 12, however, that is still not the sum-total value of nodal points involved.

We have to add #9 in there to sum-total to 13 nodal points for what may be the minimal quanta of Universe, the graviton/darkion.

Part Four: Tesla comments and Fullers Explorations

Here is a mythical statement attributed to Tesla “If you knew the magnificence of the three, six and nine, you would have a key to the universe.” – Nikola Tesla

My inside-the-tube { ergo nuclear } reality is as sine-wave { /\/\/ } patterned topology as 0, 3, 6, 9, 12, 18, 21, 24 etc.

The regular/symmetrical 5-fold icosa{20}hedron has 31, left and right-skew, primary great circles, when referenced to the left or right contraction-expansion ---see jitterbug at http://www.rwgrayprojects.com/synerg...igs/f6008.html of the4-fold cubo{6}-octa{8}hedron aka Vector Equilibrium { R.B. Fuller } that, has 24 chords/lines.
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"My education has been of my biggest impediments to my learning"...A. Einstein

"The first principle is that you must not fool yourself and you are the easiest person to fool."...R Feynman
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Old 21-04-2019, 03:01 PM
r6r6r r6r6r is offline
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Book1 Missing Process

Oops I left out key process so adding it in here below.



Pi^4 { 3D-XYZ + time } = 97.4, however if we substract the XYZ{ 3D } Pi-based 31, we then arrive at Pi-Time.


so 97.4 minus 31 = Pi-Time { 66.4 }
...time = /\/\/\/ aka frequency i.e. frequency of events...



31.00 62 7 66 and that is #7 in the overall 7th position as found in Pi^3{ XYZ aka 3D } 31.00


24.35 22 7 27 and that is #7 in 7th position as found in Pi^4/4{ re-normalization } aka Pi-Time { 66.4 }


7-color mapping of torus surface


7 axi of Operating System of Universe { Vector Equilibrium } surface polygons LINK



.....3 axi of diametrically opposing surface squares


.....3 axi of diametrically opposing surface triangles
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"My education has been of my biggest impediments to my learning"...A. Einstein

"The first principle is that you must not fool yourself and you are the easiest person to fool."...R Feynman
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  #3  
Old 23-04-2019, 04:56 PM
r6r6r r6r6r is offline
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Book1

Previously I presented to kinds of great circle associated with a torus;


1 } ( )( ) is two equatorial { great } cross sectional planes of the tube --not whole torus-- so either one is great circle,

2} ( ( ( ) ) ) the central ---inside-the-tube--- great circle plane divides the whole torus into two equal halves.

How the greatly reduced Pi, 0.007 is applied to a torus is difficult to make sense of, in a rational, logical common sense way. The most practical conclusion Ive arrived at is to see how Pi-time 66. 4 is applied.

What I came to is to think of --for starters--- is that my numerical-based, spiral-helixed torus, has 66.4 revolutions around-the-tube, as the process for process of creating a whole torus.


/ / / / / / / / / / / / / / / / / / / / / / = 22 spiral revolutions

/ / / / / / / / / / / / / / / / / / / / / / = 22 "" ""

/ / / / / / / / / / / / / / / / / / / / / / = 22 "" ""

...............................................= 66 total


The .4 means that the spiral inverts --going inside the tube--- before making thye 67th revolution. I break this above into three sections of 22, because my geometric Standard Model associates the electron with the three great circles{ planes } of the octa{8}hedron, that are each perpendicular { 90 degrees } to the other.


It may be too early to bring this into view, but in Synergetics we see that the octahedron as developed by the VE/jitterbug process, is actually composed of three sets of double-bonded/valenced great circles or planes ergo a set of 6 great circles or planes define the octahedral electron that is composed of 12 sets of two double-bonded/valenced vectorial edges. LINK

Related considerations
Pi^3{ XYZ } = 31.00 62 7 66 802998
.....................................7 is in the overall 7th position.....


Pi^4{ XYZ + time }, minus 31 = 66.4 { Pi-Time }


Pi^4/4{ re-normalization to XYZ- 3D } = 24.35 22 7 27 585 00 60 9309110083172176
.................................................. .............................7 is in overall 7th position............
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Old 23-04-2019, 05:01 PM
JosephineB JosephineB is offline
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r6r6r. I hope you get someone come along to appreciate your time, effort and be able to understand.
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Old 24-04-2019, 02:20 AM
r6r6r r6r6r is offline
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Book1

Quote:
Originally Posted by JosephineBloggs
r6r6r. I hope you get someone come along to appreciate your time, effort and be able to understand.


This following formula is pretty simple, not rocket science. A 10 year old can do this on many hand held computers and especially most computers calculators and even easier if the calculator is in scientific mode.


0.0077 * 66.4 = 0.511 28 and that is close to 0.511 { electron mass }


Electron mass is not a difficult concept to grasp either.
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"Dare to be naive"... R. B. Fuller

"My education has been of my biggest impediments to my learning"...A. Einstein

"The first principle is that you must not fool yourself and you are the easiest person to fool."...R Feynman
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Old 24-04-2019, 03:23 AM
soniiiety soniiiety is offline
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sounds interesting, heard of glons n quans???
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Old 24-04-2019, 06:19 AM
JosephineB JosephineB is offline
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Quote:
Originally Posted by r6r6r
This following formula is pretty simple, not rocket science. A 10 year old can do this on many hand held computers and especially most computers calculators and even easier if the calculator is in scientific mode.


0.0077 * 66.4 = 0.511 28 and that is close to 0.511 { electron mass }


Electron mass is not a difficult concept to grasp either.

I stopped being able to help my son with his maths homework when he was about 8 years old. I'll get my coat.

Best wishes with whatever you're working on.
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Old 24-04-2019, 07:06 PM
r6r6r r6r6r is offline
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Book1 ???????

Quote:
Originally Posted by soniiiety
sounds interesting, heard of glons n quans???


Glons kill people so I'm for my glon laws.


Quans give me indigestion and gas so I avoid them and unless I have a stomach pump near by.


:--)))))
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"Dare to be naive"... R. B. Fuller

"My education has been of my biggest impediments to my learning"...A. Einstein

"The first principle is that you must not fool yourself and you are the easiest person to fool."...R Feynman
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Old 21-05-2019, 02:18 PM
7luminaries 7luminaries is offline
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Quote:
What I came to is to think of --for starters--- is that my numerical-based, spiral-helixed torus, has 66.4 revolutions around-the-tube, as the process for process of creating a whole torus.
Hey there r6...interesting stuff as usual.
This shape was the basis of traversing the quantum realm in Avengers Endgame - entering and exiting the quantum realm via "Pym Particles" at some key points, or turns in the spiral. However it pretty much fell apart right from there, LOL. Even if all that technology really existed to physically "travel through time".

Since all those different timelines they somehow accessed or brought into being actually also mean different space/time instances. That was the main thing for me...each of those 14 million instances which meaningfully altered something are apparently completely different space/time instances and thus not connected to each other. Not just alternatives at hand in each moment brought about by different choices in each moment going forward, but instead completely different universes. Totally different instances with different "pasts" and different people living or dying. The movie mixed these two different "types" of alternate universes (one a common variant which exists in each new moment, one a completely different instance of space/time all together -- which can only exist if the original space/time instance of the universe is destroyed).

I think I would have liked it better if everyone had just accepted and moved on .
Though I suppose the only thing that made it semi-believeable was Dr Strange who is the equivalent of a time lord, LOL

Peace & blessings
7L
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Old 23-05-2019, 02:48 PM
r6r6r r6r6r is offline
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Quote:
Originally Posted by 7luminaries
Dr Strange who is the equivalent of a time lord, LOL
Peace & blessings
7L


Hi 7L. Yeah I really enjoyed that Marvel movie.


3.14 = Pi ----ratio of perfect circle circumference to its diameter { two radii }

3.113 * 66.4 = 206.7032 approximate electron-muon mass


0.0077 * 66.4 = 0.511 28 approximate electron mass


66.4 is my Pi-Time and explained further below in part two.
....Pi^4 - 31 = 66.4....


Electron mass is 0.511 and the electron repeats itself as the muon-electron and that mass is much greater as 206.7572826.


I.e., 0.511 plus 206.2462826 = the mass of muon-electron 206.7572826


Above, I change the value of Pi { 3.14 } to 0.0077.


The problem for my pathway forward is the number 0.00077 is not only close to Pi{ 3.14 } is is less than 1{ one }.



So, if I dont want to change the value of 66.4,


nor not associate 66.4 with my numerical torus with its sine-wave inversions (><)(><),


then, what exactly is that 0.00077 going to be associated with in the context of my torus?


A torus has two primary kinds of great circle;


1} one that defines bisection the tube OO{ two bisections }, and,


2} one that is inside outer peak-of-positive-curvature of the whole torus ( ( ) ).


However, over the years, before my torus came along, I considered the electron to be associated with the octahedron, ergo the three, YXZ{ cartesian-90 degree oriented } great circle/polygonal planes of the octahedron.


The only new part of that scenario is that the great circle/polygon is a 3D torus not just 1D line. Do you understand?

If you do, then you can then follow ways of tried to reduce the number of revolutions around each of those great tori, and yet still arrive at a total value of 66.4.


66.4 / 3 = 22.1333333.....


So lets see, if we also divide 3.14 by 3, then we get value of 1.046666666...... and that is still way above 0.00077.


However, if we consider the octahedron resultant of a contracting VE/jitterbug ---see LINK---, ergo 6 great circles/polygons then we divide both values by 6.


66.4 / 6 = 11.066666 is the number of revolutions around tube --not the whole torus--- of each of the 6 tori.


3.14 / 6 = 0.52333333333... and that is still much greater than 0.00077.


0.522563 is the differrence between those two and the amount I would still need to decrease to get to 0.00077.


I think I'm going to try adding one more great circle at a time and see how manyh it takes to get close to the values I need. I can already see the problem I will have is that I'm already at 6 tori and each only has 11 revolutions.



I dont think I can go under 3 revolutions per torus. h,mmmmm?
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"The first principle is that you must not fool yourself and you are the easiest person to fool."...R Feynman
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