Tried something new in regards to the following operations, in trying to find how the 0.0077 would associate to three of my helix-based numerical tori of an octahedron.

3.14 = Pi


3.113 * 66.4 = 206.7032 approximate electron-muon mass ...{ this latter begin the value R Feynman says ever physicist has on his wall }......

0.0077 * 66.4 = 0.511 28 approximate electron mass is ok but does not associate rationally with even one whole numerical torus much less three, ergo I tried something new and got a surprise value.

8623.3 7 66 2 33 7 66 2 33 7 66 2 33 7 66 233766

So this operation of dividing 66.6 ---revolutions of helix around the tube of whole torus?--- gave me the above value. Not sure what to do with it, but I at least get a rational whole number set { 8632 } that may some how relate-able to helix based numerical torus.

Anyway that 862 and 3.3 7 66 2 33 7 66 would pop out takes me back to;

Pi^3 = 31.00 62 7 66 80

even tho there is no 33 in the latter value.
~~~~~~~~~~~~~~~~~~~~~~~~~~~

Pi^4 - 31 = 66.4090910 3400 2437 23 6440332688705

Review and new info added:

.0.0077 .....* 66.4 = 0.51128 electron mass

.3.113.........* 66.4 = 206.7032 approximate muon-electron mass

26.61 26 5 * 66.4 = 1767.038 and approximate mass of tau-electron?
.......tau is 3458 times the mass of the electon?..................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~

66.4 { revolutions within helical torus? } / 0.0077 = 8623.37 66 233766 233766 233766 233766
..................P^4 - 31 = 66.4......................

8,623.37 66 233766 233766 233766 233766

8,623 - 2,000 = 6623
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~
66.4 / 3.113 = 21.32 99 06 84 22 74 33344041117892708
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~
66.4 / 26.6126 = 2.49 50 58 73 15782749524661250685765

This following may lead to most definitive Pi-Time { 66.4 } associated with a single electron

Diameter of hydrogen atom --ergo one electron-- is 1.06 * 10 to negative 10. i.e. 1.06 * 0.1 = 0.106m and that is the value I will begin with via the torus for diameter { <--D--> } of electron.

This 0.106 is the value of the diameter of the larger circle of my numerical torus. So we want to use half of that value ---ergo 0.053--- to attain the radius { R--> } and then the resultant surface area of one torus that may be involved with the hydrogen's, single electron, fuzzy cloud.

0.053 * 12.56637061{ R--> }... = 0.66601764233

The calculation can be done different ways with different kinds of radii being used. I'm going with this following pathway since it does the math for me if I can properly assign their radii to my numerical tori. I also like this method because it approximates what I believe the tubes radius to be, however, it does subtract the value of diameter of hydrogen atoms single proton.


I assume my numerical torus inside inner radius ---via the following link--- begins at the outside surface of diameter of the single hydrogen proton ergo I will have to double the value of the inner radius in the following link so as the inner circle of the diagram.

S = π2 * (R2 - r2) LINK to calculator that does the math for us.

R{ R--> } = 0.053

r{ r--> } = 0.0 minus radius of proton and we will exclude proton values for following resultants

and the resultant surface area for my numerical torus is 0.02772372 ---and that value includes protons diameter---.

Next I need to establish a connection/association to Pi-Time 66.4 ie. 66.4 revolutions { inversions } and subtract that from volume{?}?